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H3C Large-Scale Routing Network Technologies V2.0 Sample Questions:

1. 如图所示, RTB 、 RTC 与 RTA 建立 IBGP 对等体,且 RTA 为 RTB 和 RTC 的反射器。目前 RTA 和 RTC 为连接 Internet 的出口路由器。
为了使 RTB 经过 RTA 或 RTC 访问因特网,在 RTA 和 RTC 上配置了缺省路由,并使用 network 命令进行了发布。以下说法正确的是 _____ 。

A) 如果实现 RTB 优选 RTC 访问 Internet ,则需要 RTB 和 RTC 之间建立对等体关系并设置相关路由属性。
B) RTB 上形成两条等价缺省路由。
C) RTB 优选 RTA 和 RTC ,取决于 RTA 和 RTC 发布的缺省路由属性。
D) RTB 优选 RTA 访问 Internet ,因为到达 RTA 的路径更短。

2. 下列关于路由表与 FIB 表的说法,哪些是正确的 ?

A) 路由表中的表项来源于 FIB 表
B) 路由表中处于活跃（ Active )状态的路由可导入到 FIB 表中
C) FIB 表项也可能来源于 ARP 表
D) 通过 displaip routing-table 命令查看发现路由表发生了变化,则 FIB 表也肯定会发生变化

3. 在如图所示的拓扑中, RTA 、 RTB 、 RTC 和 RTD 上分别执行如下配置:
RTA-LoopBack0] ip address 1.1.1.1 255.255.255.255
RTA]ospf 1
RTA-ospf-1]area 1
RTA-ospf-1-area-0.0.0.1]network 10.0.0.0 0.0.0.255
RTA-ospf-1]import-route direct
RTB-LoopBack0] ip address 2.2.2.2 255.255.255.255
RTB]ospf 1
RTB-ospf-1]area 1
RTB-ospf-1-area-0.0.0.1]network 10.0.0.0 0.0.0.255
RTB-ospf-1-area-0.0.0.1]area 0
RTB-ospf-1-area-0.0.0.0]network 20.0.0.0 0.0.0.255
RTB-ospf-1]import-route direct
RTC-LoopBack0] ip address 3.3.3.3 255.255.255.255
RTC]ospf 1
RTC-ospf-1]area 0
RTC-ospf-1-area-0.0.0.0]network 20.0.0.0 0.0.0.255
RTC-ospf-1-area-0.0.0.0]area 2
RTC-ospf-1-area-0.0.0.2]nssa
RTC-ospf-1-area-0.0.0.2]network 30.0.0.0 0.0.0.255
RTC-ospf-1-area-0.0.0.2]network 3.3.3.3 0.0.0.0
RTD-LoopBack0] ip address 4.4.4.4 255.255.255.255
RTD]ospf 1
RTD-ospf-1]area 2
RTD-ospf-1-area-0.0.0.2]network 30.0.0.0 0.0.0.255
RTD-ospf-1-area-0.0.0.2]nssa
RTD-ospf-1]import-route direct
RTD 的路由表中不可能存在以下哪些路由 ______ 。

A) 1.1.1.1/32
B) 0.0.0.0/0
C) 2.2.2.2/32
D) 3.3.3.3/32

4. 以下关于 as-path list 的描述,正确的有 ______________ 。

A) as-path lis 的名字可以使用数字,也可以使用字符
B) as-path lis 使用正则表达式定义
C) 一个 as-path list 可以配置多个表项,表项之间是或的关系
D) as-path list 分为 basic 和 advanced 两种。

5. 如图组网中,如果要求 RTA 能访问 RTB 的 2::/64 网段,则需要在 RTA 上配置如下哪个命令 ?

A) RTA]ipv6 route-static 2::64 ethernet0/0 2::1
B) RTA]ipv6 route-static 2::64 ethernet0/0 fe80::2
C) RTA]ipv6 route-static 2::64 2::1
D) RTA]ipv6 route-static 2::64 fe80::2

Solutions: